Molarity and Storchiometry
Eg. How many grams of Ag will be formed when 100ml of 0.500M AgNO3 is reacted with sufficient Mg?
Mg + 2AgNO3 →2Ag + Mg (NO3)2
- first, we can calculate how many moles is contained in the reaction
100ml=0.100L*0.500M=0.05moles of AgNO3
- Then we can convert moles AgNO3 to moles of Ag and converts to grams Ag
0.05moles AgNO3 *(2mole Ag/ 2 mole AgNO3) * (107.9g/1 mole Ag) =5.40g of Ag
Eg2: How many mL of 0.300M AgNO3 are required t oreact with 3.00 grams of Mg?
- Equation: Mg + 2AgNO3 → 2Ag + Mg(NO3)2
- Then we can covert grams Mg to moles Mg. Moles Mg to moles AgNO3 and to ML
3.00g Mg * (1 mole Mg/24.3g) * (2 mole AgNO3 / 1 mole Mg) =0.247 moles of AgNO3
0.247Moles AgNO3 / 0.300M = 0.823L of AgNO3 = 823mL
Gas Stoichiometry
Eg. Water decomposes into H2 and O2, how many grams of H2O are needed to produce 5.0L of O2 measured at STP?
2H2O → 2H2 + O2
5.0L * (1 mole O2 / 22.4L) *(2 moles H2O / 1 mole O2)* (18g/ 1 mole H2O) =8.0g of H2O
-Here we convert L to moles(in STP) and then converts mole of O2 to mole of H2O and to grams of H2O
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